How to read text file line by line in Python? I have a text file with content like this :
12345678
b23dafgd3ddasad3dda
12345678
4befddafgd3ddasad3dda
12345678
2dcfdafgd3ddasad3dda
12345678
64befddafgd3ddasad3dda
I need the output to be like this:
12345678
b23dafgd3ddasad3dda
12345678
4befddafgd3ddasad3dda
12345678
2dcfdafgd3ddasad3dda
12345678
64befddafgd3ddasad3dda
I need to split every second line by the content between the first " " and the second " " in the string. Any ideas?
A:
You could use the open() function to open the file and read() to read each line:
with open('file.txt', 'r') as file:
for line in file.read().splitlines():
print line
Then, if you wanted to extract the data in that line, you could use the split() function to split the line on whitespace, then split() again on the first space:
with open('file.txt', 'r') as file:
for line in file.read().splitlines():
data = line.split()[0].split(' ')[1:]
print(data)
EDIT
If you wanted to iterate over the lines in the file and print the data out, you could use something like this:
with open('file.txt', 'r') as file:
for line in file.read().splitlines():
print(line)
Q:
Convert vector to list of vectors
Let's say I have a vector
c(5,7)
and I want to convert it to a list
list(c(5,7))
So as to then get a list of two vectors like
list ac619d1d87
Related links: